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(-16x^2)+275x-210=0
We get rid of parentheses
-16x^2+275x-210=0
a = -16; b = 275; c = -210;
Δ = b2-4ac
Δ = 2752-4·(-16)·(-210)
Δ = 62185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(275)-\sqrt{62185}}{2*-16}=\frac{-275-\sqrt{62185}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(275)+\sqrt{62185}}{2*-16}=\frac{-275+\sqrt{62185}}{-32} $
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